2y^2-16y-160=0

Solution for 2y^2-16y-160=0 equation:

2y^2-16y-160=0

a = 2; b = -16; c = -160;
Δ = b2-4ac
Δ = -162-4·2·(-160)
Δ = 1536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1536}=\sqrt{256*6}=\sqrt{256}*\sqrt{6}=16\sqrt{6}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16\sqrt{6}}{2*2}=\frac{16-16\sqrt{6}}{4}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16\sqrt{6}}{2*2}=\frac{16+16\sqrt{6}}{4}
$